8m^2+26m-7=180

Solution for 8m^2+26m-7=180 equation:

8m^2+26m-7=180

We move all terms to the left:

8m^2+26m-7-(180)=0

We add all the numbers together, and all the variables

8m^2+26m-187=0

a = 8; b = 26; c = -187;
Δ = b2-4ac
Δ = 262-4·8·(-187)
Δ = 6660
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6660}=\sqrt{36*185}=\sqrt{36}*\sqrt{185}=6\sqrt{185}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-6\sqrt{185}}{2*8}=\frac{-26-6\sqrt{185}}{16}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+6\sqrt{185}}{2*8}=\frac{-26+6\sqrt{185}}{16}
$